Baseball Player Profile

Austin Meadows

Positions: Left Fielder
Jersey Number: 17
Bats: Left
Throws: Left
Height: 6' 3" (191cm)
Weight: 225lbs (102kg)
Professional Debut Date: May 18, 2018
Birth Date: May 3, 1995 (Age 28)
Birth Place: Atlanta, GA
Summary
GP
AB
H
HR
BA
R
RBI
SB
SO
OBP
SLG
OPS
2023
6
21
5
0
.238
0
2
0
3
.238
.286
.524
Career
417
1507
390
70
.259
209
238
23
363
.333
.472
.805
 

FAQs

  • How old is Austin Meadows?
    • Austin Meadows is 28 years old and was born on May 3, 1995..
  • Where was Austin Meadows born?
    • Austin Meadows was born in Atlanta GA in USA.
  • How tall is Austin Meadows?
    • Austin Meadows is 6' 3" (191cm) tall.
  • How much does Austin Meadows weigh?
    • Austin Meadows weighs 225 pounds (102 kilograms).
  • How many seasons has Austin Meadows played?
    • Austin Meadows has played for 5 years, having made their professional debut on May 18, 2018.
  • What position does Austin Meadows play?
    • Austin Meadows plays Left Fielder.
  • How many hits does Austin Meadows have?
    • Austin Meadows has 390 hyd over the course of their career.
  • How many home runs does Austin Meadows have?
    • Austin Meadows has hit 70 home rund over the course of their career.
  • What is Austin Meadows's average?
    • Austin Meadows batting average is .259.
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